4n=(n^2+4n)-n^2

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Solution for 4n=(n^2+4n)-n^2 equation: 



4n=(n^2+4n)-n^2

We move all terms to the left:

4n-((n^2+4n)-n^2)=0



We calculate terms in parentheses: -((n^2+4n)-n^2), so:

(n^2+4n)-n^2

determiningTheFunctionDomain
-n^2+(n^2+4n)

We add all the numbers together, and all the variables

-1n^2+(n^2+4n)

We get rid of parentheses

-1n^2+n^2+4n

We add all the numbers together, and all the variables

4n

Back to the equation:

-(4n)



We add all the numbers together, and all the variables

=0

n=0/1

n=0

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